The molecule does not exist.

However if you look at azulene, it’s possible to push the arrows such that you get a cyclopentadienyl cation and a heptatrienyl anion, each of which are (in theory) anti aromatic. However based on the dipole moment the contribution of this resonance form is zero

It’s not conjugated all the way around the ring. If you look at the nitrogen you’ll see that it is sp3 hybridized (attached to four sigma bonds). If it had an empty p orbital that would give it 5 orbitals which violates the octet rule!

Because the ring meets the rules. : – )

The methyl group has no impact on the aromaticity. Aromaticity is determined by the pi-electrons (i.e. the electrons in the double bonds).

Thanks in advance!

Count the pi electrons and that should tell you!